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Standard XIII

Chemistry

Potassium Permanganate

In the redox ...

Question

In the redox titration using potassium permanganate, the acidification is usually done using $H_{2} S O_{4}$ instead of $H C l$ . Why?

H_{2} S O_{4}

is stronger acid than

H C l

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H C l

is oxidised by

K M n O_{4}

C l_{2}

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H_{2} S O_{4}

is a dibasic acid.

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Only

H_{2} S O_{4}

is completely ionised.

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Solution

The correct option is B $H C l$ is oxidised by $K M n O_{4}$ to $C l_{2}$ .
Use of $H C l$ is avoided as $K M n O_{4}$ oxidises $H C l$ to $C l_{2}$ gas.
$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2} .$
Hence option (b) is correct.

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Similar questions

Q. In the redox titration using potassium permanganate, the acidification is usually done using

H_{2} S O_{4}

instead of

H C l

. Why?

Q. Though alkaline potassium permanganate and acidic potassium permanganate both are used as oxidants, yet in the manufacture of benzoic acid from toluene we use alcoholic potassium permanganate as an oxidant. Why? Write the balanced redox equation for the reaction.

Q. Assertion :In titrations involving potassium permanganate no indicator is used . Reason:

M n O_{4}^{-}

acts as the self - indicator.

How do you count for the following observations?
Though alkaline potassium permanganate and acidic potassium permanganate both are used as oxidants, yet in the manufacture of benzoic acid from toluene we use alcoholic potassium permanganate as an oxidant. Why? Write a balanced redox equation for the reaction.

When concentrated sulphuric acid is added to an inorganic mixture containing chloride, we get colourless pungent smelling gas HCl, but if the mixture contains bromide then we get red vapour of bromine. Why?

Q. Why is potassium permanganate used for purifying drinking water?

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Potassium Permanganate

Standard XIII Chemistry

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In the redox titration using potassium permanganate, the acidification is usually done using H2SO4 instead of HCl. Why?

The correct option is B HCl is oxidised by KMnO4 to Cl2.Use of HCl is avoided as KMnO4 oxidises HCl to Cl2 gas. 2KMnO4+16HCl→2KCl+2MnCl2+8H2O+5Cl2. Hence option (b) is correct.

In the redox titration using potassium permanganate, the acidification is usually done using $H_{2} S O_{4}$ instead of $H C l$ . Why?

The correct option is B $H C l$ is oxidised by $K M n O_{4}$ to $C l_{2}$ .
Use of $H C l$ is avoided as $K M n O_{4}$ oxidises $H C l$ to $C l_{2}$ gas.
$2 K M n O_{4} + 16 H C l \to 2 K C l + 2 M n C l_{2} + 8 H_{2} O + 5 C l_{2} .$
Hence option (b) is correct.