wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In the Solvay process for producing sodium carbonate (Na2CO3), the following reactions occur in sequence.
NH3+CO2+H2ONH4HCO3
NH4HCO3+NaClNH4Cl+NaHCO3
2NaHCO3ΔNa2CO3+H2O+CO2
How much of Na2CO3 would be produced per kg of NH3 used if the process were 100% efficient?

A
3.12 kg
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1.00 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
2.00 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.56 kg
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 3.12 kg
Based on stoichiometry,
1 mol Na2CO3 is obtained from 2 mol NH3

106 g Na2CO3 is from =2×17 g NH3
34 g NH3 gives = 106 g Na2CO3
Thus, 1000 g NH3 gives =106×100034g Na2CO3
=3118 g Na2CO3
=3.118 kg Na2CO3

flag
Suggest Corrections
thumbs-up
5
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Stoichiometric Calculations
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon