In this electrochemical cell the direction of current is .

zinc to copper rod

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copper to zinc rod

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anode to cathode

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Solution

The correct option is B copper to zinc rod
Electrons flow from the negative terminal to the positive terminal and the flow of current is opposite of this.

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Similar questions

Z n | Z n^{2 +} | | H^{\oplus} | (H_{2}) P t

E_{c e l l} =_{c e l l}^{⊖}

M | M^{+} ∥ X^{-} | X

E_{(M^{+} | M)}^{o} = 0.44 V

E_{(X | X^{-})}^{o} = 0.33 V

0.5 a m p

P t | H_{2} (x a t m) | H^{\oplus} (p H = y) | | Z n^{2 +} (z M) | Z n

E_{c e l l}^{⊖} = E_{c e l l}

In an electrochemical cell represented as,

Zn | Zn²⁺₍c₁₎ || Cu²⁺₍c₂₎| Cu

So in this cell,

a.Zn is oxidized

b.Zn is reduced

c.Cu is oxidized

d.Cu is reduced

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