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Higher Order Derivatives

In ABC, rig...

Question

In $△ A B C$ , right-angled at $B, A B = 24 c m$ , $B C = 7 c m$ . Determine
(i) $sin A, cos A$
(ii) $sin C, cos C$

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Solution

$A C^{2} = A B^{2} + B C^{2} = 24^{2} + 7^{2} = 625$
$A C = 25 c m$
(i) $sin A = \frac{B C}{A C} = \frac{7}{25}; cos A = \frac{A B}{A C} - \frac{24}{25}$

(ii) $sin C = \frac{A B}{A C} = \frac{24}{25}; cos C = \frac{B C}{A C} - \frac{7}{25}$

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Similar questions

In ΔABC right angled at B, AB = 24 cm, BC = 7 cm. Determine

(i) sin A, cos A

(ii) sin C, cos C

A B C

B, A B = 24 c m, B C = 7 c m

sin A, cos A

sin C, cos C

Δ

A B = 24

B C = 7

sin A, cos A

sin C, cos C

△ A B C

B,

A B = 24 c m, B C = 7 c m

s i n A, c o s A

s i n C, c o s B

△ A B C

B

A B = 24 c m, B C = 7 c m

: (i) sin A, cos A, (i i) sin C, cos C

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