Question

In what ratio should a $80\%$ (mass/volume) solution of $H_{2}S{O}_4$ be mixed to $20\%$ (mass/volume) of $H_{2}S{O}_4$ to produce $40\%$ (mass/volume) $H_{2}S{O}_4$ solution?

• A. $2:1$
• B. $1:2$
• C. $1:3$
• D. $3:1$

Answer 1

The correct option is B $1:2$

Let $V_1$ mL of $80\%$ and $V_2$ mL of $20\%$ of $H_{2}S{O}_4$ be mixed.
$V_1\times 80+V_2\times 20=40(V_1+V_2)$
$40V_1=20V_2$
$\frac{V_1}{V_2}=\frac{1}{2}$