Question

In which of the following compound hybridisation of bridging atom is different from hybridisation of central atom?

• A. $A{l}_2(C{H}_3{)}_6$
• B. $I_{2}C{l}_6$
• C. Solid $BeC{l}_2$
• D. $A{l}_2(OH{)}_6$

Answer 1

The correct option is B $I_{2}C{l}_6$

a) Structure of $A{l}_2(N{H}_2{)}_6$ is:
Bridging Atom is $N$ and Central atom is $Al$.
Steric number for $Al$ = 4 (4$\sigma$ Bond pair)
i.e Hybridisation is $s{p}^3$
Steric number for $N$ = 4 (4$\sigma$ Bond pair)
i.e Hybridisation for $N$ is also $s{p}^3$


b) Structure of $I_{2}C{l}_6$ is:

Bridging Atom is $Cl$ and Central atom is $I$.
Steric number for $I$ = 6 (4$\sigma$ Bond pair + 2 Lone pair)
i.e Hybridisation is $s{p}^3{d}^2$
Steric number for $Cl$ = 4 (2$\sigma$ Bond pair + 2 Lone pair)
i.e Hybridisation for $O$ is $s{p}^3$

c) In the solid state, $BeC{l}_2$ has polymeric chain structure.


Bridging Atom is Chlorine and Central atom is $Be$.
Steric number for $Be$ = 4 (4 Bond pair)
i.e Hybridisation is $s{p}^3$
Steric number for $Cl$ = 4 (2 Bond pair + 2 Lone pair)
i.e Hybridisation for $Cl$ is also $s{p}^3$

d) In $A{l}_2(OH{)}_6$
Bridging Atom is $O$ and Central atom is $Al$.
Steric number for $Al$ = 4 (4$\sigma$ Bond pair)
i.e Hybridisation is $s{p}^3$
Steric number for $O$ = 4 (3$\sigma$ Bond pair + 1 Lone pair)
i.e Hybridisation for $O$ is also $s{p}^3$