In which of the following compounds, is the oxidation number of sulphur is the least?

S O_{2}

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S O_{3}

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N a_{2} S_{4} O_{8}

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H_{2} S O_{4}

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Solution

The correct option is C $N a_{2} S_{4} O_{8}$
The oxidation number of sulphur in $S O_{2}, S O_{3}, N a_{2} S O_{4}$ and $H_{2} S O_{4}$ are $+ 4, + 6, + 2.5$ and $+ 6$ respectively. Hence, it is least in $N a_{2} S O_{4}$ .

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x = H_{2} S O_{4}; y = H_{2} S O_{5}; z = H_{2} S_{2} O_{8}

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