The correct option is
C ![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1029820/original_73.PNG)
In Keto-enol tautomerism, delocalisation takes place between a >C=O group and an alpha H where the equilibrium lies between a keto form and an enol form.
In (a), the keto form is more stable than enol form because the enol form has 4-
π electrons which obeys 4n rule and thus it is an antiaromatic so it is less stable. So Keto form dominates over enol.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1029853/original_74a.PNG)
In (b), the keto form is more stable because in enol form double occurs at bridgehead carbon so by Bredt's rule it is less stable. Hence keto form dominates enol form.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1029855/original_72a.PNG)
In (c), the Keto form is more stable because in enol form due to steric hindrance of bulky tertiary alkyl group the H-bonding is less favoured, hence enol form becomes less stable.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1029857/original_73a.PNG)
In (d), enol form dominates over keto form because the enol form is stabilised by conjugated double bond and by the formation of 6 membered cyclic ring by hydrogen bonding. Thus, enol group dominates over keto form.
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1029849/original_71a.PNG)
Therefore, in (a), (b) and (c) keto form is dominating.