Increase 243 in the ratio- 3 - 11891-198-981-689-

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Byju's Answer

Standard VI

Mathematics

Increase or Decrease in a Given Ratio

Increase 243 ...

Question

Increase 243 in the ratio 3 : 11

981

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689

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891

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198

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Solution

The correct option is C
891

To increase a given quantity in the given ratio a : b , we have Given quantity $\times$ $\frac{b}{a}$ where b > a

Hence New quantity = $243 \times \frac{11}{3}$

= $81 \times 11$

= 891

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Similar questions

Simplify the following expression :

$\frac{\frac{1}{2} \times (0 \times (\frac{696}{142} \times \frac{989}{789} \times \frac{456}{989} \times \frac{142}{696})) + \frac{5}{6} \times 9 \times 0}{(\frac{989}{456} + \frac{498}{981} + \frac{598}{251} + \frac{198}{256}) \times 989}$

Fill in the missing numbers/words.
$310 + 981 + 309 = 981 + 309 +___$

Q. Fill in the missing values to divide 981 by 3 using the place value division method.

981 \div 3

= (A + B + C) \div 3

= (A + D) \div 3

= (A \div 3) + (D \div 3)

= E + 27

= F

Q. 1^{243}+2^{243}+3^{243}_ _ _ _ _ _ _+243^{243}÷2^{243

Q. Increase

1200

in the ratio

3 : 7

and then increase the resulting number again in the ratio

4 : 7

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Increase 243 in the ratio 3 : 11

The correct option is C 891 To increase a given quantity in the given ratio a : b , we have Given quantity × ba where b > a Hence New quantity = 243×113 = 81×11 = 891

The correct option is C
891

To increase a given quantity in the given ratio a : b , we have Given quantity $\times$ $\frac{b}{a}$ where b > a

Hence New quantity = $243 \times \frac{11}{3}$

= $81 \times 11$

= 891