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Question
Initially ,height of water in the capillary tube is 10cm . If the capillary tube is now inclined at 45°, the length of water rising in the tube is
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Solution
use this
pi r^2 h row g sin 45 = 2 pi r s .
i.e. we take the component of the weight and equate that, not the component of the S.Tension.
put the alues
ans is 10root2
pi r^2 h row g sin 45 = 2 pi r s .
i.e. we take the component of the weight and equate that, not the component of the S.Tension.
put the alues
ans is 10root2
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