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B
No
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C
Ambiguous
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D
Data insufficient
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Solution
The correct option is A Yes LHS=1+cosθ−sinθ1+sinθ+cosθ+1+sinθ+cosθ1+cosθ−sinθ =[1+cosθ−sinθ]2+[1+sinθ+cosθ]2(1+cosθ)2−sin2θ =2+2cosθ+2+2cosθ(1−sin2θ)+cos2θ+2cosθ=4(1+cosθ)2cos2θ+2cosθ=4(1+cosθ)2cosθ(1+cosθ) =2cosθ=2secθ=RHS