Question

............... is true for discriminate of quadratic equation $x^2+x+1=0$.

• A. D = 0
• B. D < 0
• C. D > 0
• D. D is a perfect square

Answer 1

The correct option is B D < 0

The polynomial is $x^2+x+1=0$.

Comparing with $a{x}^2+bx+c=0$, we get

$a=1,b=1,c=1$

$D=b^2-4ac=1-4\left(1\right)\left(1\right)=-3<0$