Is $x = - 3$ and $y = 4$ a solution of $2 y + 3 x + 1 = 0$

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Solution

Substituting x = -3 and y = 4 in the LHS of the equation

LHS = 2y +3x +1
= 2(4) + 3(-3) +1
= 8 -9 +1
= 0
= RHS

Since x = -3 and y = 4 satisfies the given equation
Therefore, x = -3 and y = 4 is the solution of the equation.

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Find out which of the following equations have x=1, y=2 as solution.
x + 2y = 5
2y - 3x + 3 = 0
3x + 4y - 8 = 0 [4 MARKS]

x \neq 0, y \neq 0 :

\frac{1}{2 (x + 2 y)} + \frac{5}{3 (3 x - 2 y)} = \frac{- 3}{2} \frac{5}{4 (x + 2 y)} - \frac{3}{5 (3 x - 2 y)} = \frac{61}{60}

k x + 2 y = 5

3 x + y = 1

k = 1

x + 2 y = 3

5 x + k y + 7 = 0

k \neq 1

x + y = 3, 3 x - 2 y = 4

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