Examine if x = 4, y = 1 is a solution of 3x + 2y = 12 [2 MARKS]

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Solution

Calculation : 1 Mark
Result : 1 Mark

Putting x = 4, y = 1 in the equation 3x + 2y = 12,
$(3 \times 4) + (2 \times 1) = 14 \neq 12$
We see that the equation does not hold.

Hence, x = 4, y = 1 is not a solution of the given equation

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x = - 3

y = 4

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Find out which of the following equations have x=1, y=2 as solution.
x + 2y = 5
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3x + 4y - 8 = 0 [4 MARKS]

3 x - y - 2 z = 2, 2 y - z = - 1, 3 x - 5 y = 3

Solution for the given system of equation is

$\frac{x + y - 8}{2}$ = $\frac{x + 2 y - 14}{8}$ = $\frac{3 x + y - 12}{11}$

x = 2, y = 1

3 x - 2 y = 4

2 x + y = 5

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