Is { $x$ : $x^{2} - 5 x - 6 = 0$ } = {2, 3}

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Solution

We have, $x^{2} - 5 x - 6 = 0$
$\Rightarrow x^{2} - 6 x + x - 6 = 0$
$x (x - 6) + 1 (x - 6) = 0$
$\Rightarrow x = 6, 1$
Thus, the given statement is not True.

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