Isopropyl chloride +A△−→2−ethoxypropane+NaCl. The compound (A) is:
A
C2H5Cl
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B
C2H5ONa
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C
CH2N2
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D
CH3ONa
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Solution
The correct option is CC2H5ONa In this reaction, isopropyl chloride undergoes Williamson's synthesis in the presence of sodium ethoxide to form 2−ethoxypropane as a product.