Jahangir travelled from his town to city. Jahangir went to city by bicycle at the speed of 20 kmph and came back at the speed of 5 kmph. If Jahangir took 5 hours and 45 min to complete his journey, what is the distance between town and city?

15 km

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23 km

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22 km

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25 km

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30 km

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Solution

The correct option is B
23 km

Average speed of Jahangir = $\frac{2 x y}{x + y} = 8 k m p h$
⇒ Distance travelled = Speed × Time = 8 $\times$ $\frac{23}{4} = 46 K m$
⇒ Distance between city and town = $\frac{46}{2} = 23 k m$

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Jahangir travelled from his town to city. Jahangir went to city by bicycle at the speed of 20 kmph and came back at the speed of 5 kmph. If Jahangir took 5 hours and 45 min to complete his journey, what is the distance between town and city?

The correct option is B 23 km Average speed of Jahangir = 2xyx+y=8kmph ⇒ Distance travelled = Speed × Time = 8 × 234=46Km ⇒ Distance between city and town = 462=23km

The correct option is B
23 km

Average speed of Jahangir = $\frac{2 x y}{x + y} = 8 k m p h$
⇒ Distance travelled = Speed × Time = 8 $\times$ $\frac{23}{4} = 46 K m$
⇒ Distance between city and town = $\frac{46}{2} = 23 k m$