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Solubility Product

K sp AgCl> K ...

Question

$K_{s p} (A g C l) > K_{s p} (A g B r) > K_{s p} (A g I)$ . This means that____________.

A g C l

is more ionised than

A g B r

and

A g I

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Both

A g B r

and

A g I

are less soluble than

A g C l

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A g I

is most soluble

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A g B r

is more soluble than

A g C l

but less soluble than

A g I

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Solution

The correct option is B Both $A g B r$ and $A g I$ are less soluble than $A g C l$
Higher the $K_{s p}$ greater will be the solubility so $A g C l$ is much more soluble than $A g B r$ and $A g I$ .

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