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Question

Kw for H2O is 9.62×1014 at 60C
The pH of water at this temperature is :

A
6.5
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B
7.5
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C
7
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D
6
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Solution

The correct option is A 6.5
We know that,
Kw=[H+] [OH]
As water is neutral and for a neutral solution:
[H+]=[OH]Kw=[H+]2Kw=9.62×1014 (Given)[H+]2=9.62×1014 [H+] =9.62×1014=31×108pH=log10[H+]pH=log10(31×108)pH=6.5

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