Ksp of is . Its solubility in will be
The explanation for the correct option:
Option (A)
Step 1: Given data
Ksp of
Step 2:Calculating Solubility and Solubility product
Dissociation of is given as
Solubility product Solubility of Silver ion solubility of chloride ion
Let the Solubility of chloride and silver ions be “s”
Dissociation of
Since there are no common ions present at the addition of , the solubility remains unaffected.
Therefore, Solubility of in
Hence, option (A) is correct.