Length of the fence of a trapezium-shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field, given that side AB is perpendicular to the parallel sides AD and BC.
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Solution
BC = 48m, CD = 17m, AD = 40m and perimeter = 120 m
Perimeter of trapezium ABCD = AB + BC + CD + DA ⇒ 120 = AB + 48 + 17 + 40 ⇒ 120 = AB + 105 ⇒ AB = 120 - 105 = 15m
Now Area of the field = 12×(BC+AD)×AB
= 12×(48+40)×15=12×88×15
= 660m2
Hence are of the field ABCD is = 660m2