Let A be a non-empty set such that A×A has 16 elements among which three elements are found to be (a,b),(b,c) and (c,d) and IA be the identity relation on A, then
A
A={a,b,c}
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B
IA={(a,a),(b,b),(c,c)}
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C
A={a,b,c,d}
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D
IA={(a,a),(b,b),(c,c),(d,d)}
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Solution
The correct option is DIA={(a,a),(b,b),(c,c),(d,d)} n(A×A)=16 ⇒n(A)=4 ⇒A={a,b,c,d} ⇒IA={(a,a),(b,b),(c,c),(d,d)}