Let fx- sin x 1- -2x- x-2- If fx is continuous at x-2 then f-2 is

The correct option is B 1 lim_x→π2 f(x) = lim_x→π2 e^(sin x) 1π 2x By L hospitals rule #160;this limit is equal to lim_x→π2 #160;e^cos x 2= ...

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Algebra of Derivatives

Let fx= sin...

Question

Let $f (x) = {(sin x)}^{\frac{1}{π - 2 x}}, x \neq \frac{π}{2}$ . If $f (x)$ is continuous at $x = \frac{π}{2}$ then $f (\frac{π}{2})$ is

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f (x) = \frac{1 - tan x}{4 x - π}

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f (x) = \frac{\sqrt{2 + c o s x - 1}}{(π - x^{2})}

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f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} \frac{1 - {sin}^{2} x}{3 {cos}^{2} x}, a, \frac{b (1 - sin x)}{{(π - 2 x)}^{2}} \end{matrix} \begin{matrix} x < \frac{π}{2} x = \frac{π}{2} x > \frac{π}{2} \end{matrix}

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