Question

Let $g\left(x\right)=1+x-\left[x\right]$ and $f\left(x\right)=\{\begin{array}{cc}-1,& x<0\\ 0,& x=0,\text{then for all}\\ 1,& x>0\end{array}$ $x,f\left[g\right(x\left)\right]$ is equal to:

Answer 1

$g\left(x\right)=1+x-\left[x\right]$ is greater than 1
since $x-\left[x\right]>0$
$f\left[g\right(x\left)\right]=1$, since $f\left(x\right)=1$ for all $x>0.$