Question

# Let g(x)=1 + x - [x] and f(x) =⎧⎪⎨⎪⎩−1x<00,x=01,x>0 then for all x, f[g(x)] is equal to: (IIT 2001)

A
x
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B
1
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C
f(x)
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D
g(x)
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Solution

## The correct option is A 1g(x) = 1 + x - [x] is greater than 1 since x - [x] > 0 f{g(x)} = 1 since f(x) = 1 for all x > 0 Therefore, (b) is the answer.

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