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Question

Let g(x)=1+x[x] and f(x)=1,x<00,x=01,x>0
Then for all x, f(g(x)) is equal to

A
x
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B
1
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C
f(x)
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D
g(x)
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Solution

The correct option is B 1
g(x)=1+x[x];
f(x)=1,x<00,x=01,x>0
For integral values of x; g(x) = 1
For x < 0; (but not integral value) x[x]>0g(x)>1
For x > 0; (but not integral value) x[x]>0g(x)>1
g(x)1,x f(g(x))=1,x

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