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Question

Let P(n)=x2nāˆ’1+y2nāˆ’1 is divisible by x+y as P(1) is true, then truth of P(k+1) indicates

A
P(n) s divisible by x+y only for odd positive integer
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B
P(n) is divisible by x+y only for positive even integer
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C
P(n) is true nN
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D
P(k) is true
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Solution

The correct option is C P(n) is true nN
This is the basic principle of mathematic induction that if P(1) is true and P(k+1) is true, then P(n) must be true nN.

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