Let P(n)=x2nā1+y2nā1 is divisible by x+y as P(1) is true, then truth of P(k+1) indicates
A
P(n) s divisible by x+y only for odd positive integer
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B
P(n) is divisible by x+y only for positive even integer
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C
P(n) is true ∀n∈N
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D
P(k) is true
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Solution
The correct option is CP(n) is true ∀n∈N This is the basic principle of mathematic induction that if P(1) is true and P(k+1) is true, then P(n) must be true ∀n∈N.