Let a- and b- be two non-collinear vectors and -a- - -b- - 1- If U- - a- - a-b-b- then -U-a- is

The correct options are A |a⃗×b⃗| B |U⃗| C |U⃗×a⃗| D |U⃗×b⃗| U⃗ .a⃗ =a⃗ .a⃗ ( a⃗ .b⃗ #160; ) #160; ^ 2 =1 abcos ^ 2 θ #160; ...

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Applications of Dot Product

Let a⃗ and ...

Question

Let $\to a$ and $\to b$ be two non-collinear vectors and $| \to a | = | \to b | = 1$ . If $\to U = \to a - (\to a \cdot \to b) \to b$ then $\sqrt{\to U \cdot \to a}$ is

| \to a \times \to b |

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| \to U |

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| \to U \times \to a |

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| \to U \times \to b |

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Solution

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Similar questions

\to a

\to b

\to u = \to a - (\to a . \to b) \to b

\to v = \to a \times \to b,

| \to v |

\to u = \to a - \to b, \to v = \to a + \to b

| \to a | = | \to b | = 2

| \to u \times \to v |

$I f \to u = \to a - \to b a n d \to v = \to a + \to b a n d | \to a | = | \to b | = 2, t h e n | \to u \times \to v | =$

\to u = \to a \times (\to b \times \to c) + \to b \times (\to c \times \to a) + \to c \times (\to a \times \to b)

\to u =

\to u = \to a - \to b; \to v = \to a + \to b

| \to a | = ∣ ∣ \to b ∣ ∣ = 2

| \to u \times \to v |

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