Light of wavelength 5000 $A^{o}$ falls on a sensitive plate with photoelectric work function 1.9eV. The maximum kinetic energy of the photoelectrons emitted will be

0.58 e V

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2.48 e V

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1.24 e V

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1.16 e V

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Solution

The correct option is A $0.58 e V$
$λ = 5000 A^{0} = 500 n m$
$K . E ._{m a x} = \frac{h c}{λ} - ϕ$

$= \frac{1240}{500} - 1.9 (h c = 1240 e V - n m)$

$= 2.48 - 1.9$
$= 0.58 e V$
So, the answer is option (A).

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Light of wavelength 5000 Ao falls on a sensitive plate with photoelectric work function 1.9eV. The maximum kinetic energy of the photoelectrons emitted will be

The correct option is A 0.58 eVλ=5000A0=500nmK.E.max=hcλ−ϕ=1240500−1.9 (hc=1240eV−nm)=2.48−1.9=0.58 eVSo, the answer is option (A).

Light of wavelength 5000 $A^{o}$ falls on a sensitive plate with photoelectric work function 1.9eV. The maximum kinetic energy of the photoelectrons emitted will be

The correct option is A $0.58 e V$
$λ = 5000 A^{0} = 500 n m$
$K . E ._{m a x} = \frac{h c}{λ} - ϕ$

$= \frac{1240}{500} - 1.9 (h c = 1240 e V - n m)$

$= 2.48 - 1.9$
$= 0.58 e V$
So, the answer is option (A).