Light traveling in air falls at an incidence angle of $2^{\circ}$ on one refracting surface of a prism of refractive index 1.5 and angle of refraction $4^{\circ}$ . The medium on the other side is water $(μ = \frac{4}{3})$ . Find the deviation produced in degree by the prism. ___

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Solution

$S i n 2^{\circ} = \frac{3}{2} s i n r_{1} r_{1} = \frac{4^{\circ}}{3} r_{2} = A - r_{1} = \frac{8^{\circ}}{3} \frac{3}{2} s i n r_{2} = \frac{4}{3} s i n e e = \frac{9}{8} r_{2} = 3^{\circ} δ = i + e - A = 2^{\circ} + 3^{\circ} - 4^{\circ} δ = 1^{\circ}$

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Light traveling in air falls at an incidence angle of 2∘ on one refracting surface of a prism of refractive index 1.5 and angle of refraction 4∘. The medium on the other side is water (μ=43). Find the deviation produced in degree by the prism. ___

Sin2∘=32sinr1r1=4∘3r2=A−r1=8∘332sinr2=43sinee=98r2=3∘δ=i+e−A=2∘+3∘−4∘δ=1∘

Light traveling in air falls at an incidence angle of $2^{\circ}$ on one refracting surface of a prism of refractive index 1.5 and angle of refraction $4^{\circ}$ . The medium on the other side is water $(μ = \frac{4}{3})$ . Find the deviation produced in degree by the prism. ___

$S i n 2^{\circ} = \frac{3}{2} s i n r_{1} r_{1} = \frac{4^{\circ}}{3} r_{2} = A - r_{1} = \frac{8^{\circ}}{3} \frac{3}{2} s i n r_{2} = \frac{4}{3} s i n e e = \frac{9}{8} r_{2} = 3^{\circ} δ = i + e - A = 2^{\circ} + 3^{\circ} - 4^{\circ} δ = 1^{\circ}$