limx→2√3−x−12−x
Rationalising the numerator
=limx→2(√3−x−1)2−x×(√3−x+1)(√3−x+1)
=limx→2(3−x)−1(2−x)(√3−x+1)
=limx→2(2−x)(2−x)(√3−x+1)
=limx→21(√3−x+1)
=1√3−2+1=11+1=12
Evaluate the following one sided limits:
(i)limx→2+x−3x2−4
(ii)limx→2−x−3x2−4
(iii)limx→0+13x
(iv)limx→8+2xx+8
(v)limx→0+2x15
(vi)limx→π−2tan x
(vii)limx→π2+sec x
(viii)limx→0−x2−3x+2x3−2x2
(ix)limx→−2+x2−12x+4
(x)limx→0+(2−cot x)
(xi)limx→0−1+cosecx