Line PQ intersects Y-axis at 0- 3 with slope -1-2 The equation of line PQ is-

The correct option is B x+2y=6 #160;Given the line PQ intersects Y axis at P(0,p)=(0,3) and its slope is=m= 1 2 . ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Slope Intercept Form of a Line

Line PQ inter...

Question

Line PQ intersects Y-axis at (0, 3) with slope $- \frac{1}{2}$ The equation of line PQ is.

x-2y=3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x+2y=6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2y-x=3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x-2y-6=0

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B x+2y=6
$G i v e n - t h e l i n e P Q i n t e r s e c t s Y - a x i s a t P (0, p) = (0, 3) a n d i t s s l o p e i s = m = - \frac{1}{2} . T o o b t a i n - t h e e q u a t i o n o f t h e l i n e . W e k n o w t h a t w h e n a l i n e P Q i n t e r s e c t s Y - a x i s a t (0, p) t h e n t h e y - i n t e r c e p t i s p . T h e e q u a t i o n o f a l i n e w i t h y - i n t e r c e p t c a n d s l o p e m i s y = m x + c . S u b s t i t u t i n g t h e v a l u e s o f m & c w e c a n g e t t h e r e q u i r e d e q u a t i o n . H e r e p = 3 & m = - \frac{1}{2} . ∴ T h e e q u a t i o n o f t h e l i n e i s y = (- \frac{1}{2} .) x + 3 ⟹ x + 2 y = 3.$

Suggest Corrections

Similar questions

The equation of the line with slope $- \frac{3}{2}$ and which is concurrent with the lines $4 x + 3 y - 7 = 0$ and $8 x + 5 y - 1 = 0$ is

Prove that the lines given by the equations 3x + 2y + 5 = 0 and 3x + 2y − 1 = 0 are parallel. At what points do they intersect the x-axis? And the y-axis?

Q. The equation of the line with slope −3/2 and which is concurrent with the lines 4x + 3y − 7 = 0 and 8x + 5y − 1 = 0 is
(a) 3x + 2y − 63 = 0
(b) 3x + 2y − 2 = 0
(c) 2y − 3x − 2 = 0
(d) none of these

Q. The equation of line passing through the point of intersection of the lines4x-3y-1=0 and 5x-2y-3=0 and parallel to the line 2y-3x+2=0, is

Q. The equation of the line perpendicular to the line

2 x + 3 y + 5 = 0

and passing through

(1, 1)

, is

Join BYJU'S Learning Program

Line PQ intersects Y-axis at (0, 3) with slope −12 The equation of line PQ is.

Line PQ intersects Y-axis at (0, 3) with slope $- \frac{1}{2}$ The equation of line PQ is.