Question

List-I contains chiral molecules and List-II contains number of stereisomers.
Which of the following has the correct combination considering List-I and List-II?

• A. $\left(II\right)\to \left(s\right)and\left(IV\right)\to \left(q\right)$
• B. $\left(II\right)\to \left(q\right)and\left(IV\right)\to \left(p\right)$
• C. $\left(II\right)\to \left(s\right)and\left(IV\right)\to \left(p\right)$
• D. $\left(II\right)\to \left(r\right)and\left(IV\right)\to \left(p\right)$

Answer 1

The correct option is D $\left(II\right)\to \left(r\right)and\left(IV\right)\to \left(p\right)$

(II) has 8 stereoisomers and (IV) has 2 stereoisomers.