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Types of Misses 1

Main memory a...

Question

Main memory access time is 200 nsec for 1 memory cell. Memory is word addressable with 1-word size of 2 Bytes. In case of cache miss a block is transferred from main memory to cache memory; which is of size 64 Bytes. Transfer bandwidth of memory is 1 GB/Sec. The total miss penalty time ________nsec.

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Solution

2B access time = 200 nsec

64B access time = 32*200 nsec
= 6400 nsec

1 GB transfer time = 1 sec

1 B transfer time $= \frac{1 s e c}{1 G} = 1 n s e c$

64 B transfer time = 64 nsec

Total miss penalty time = 6400 + 64
= 6464 nsec

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