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Types of Misses 2

Main memory a...

Question

Main memory access time is 200 nsec for 1 memory cell. Memory is word addressable with 1-word size of 2 bytes. In case of cache miss a block is transferred from main memory to cache memory; which is of size 64 bytes. Transfer bandwidth of memory is 1GB/sec.

The total miss penalty time ________ nsec.

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Solution

option (b)

2 B access time = 200 nsec

64B access time = 32*200 nsec

= 6400 nsec

1GB transfer time = 1 sec

1B transfer time = $\frac{1 s e c}{1 G}$ = 1 n sec

64B transfer time = 64 nsec

Total miss penalty time = 6400 + 64

= 6464 nsec

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