Question

Mark (✓) against the correct answer
In the given figure, ∠A = 50°, CE || BA and ∠ECD = 60°
Then, ∠ACB = ?



(a) 50°
(b) 60°
(c) 70°
(d) 80°

Answer 1

$$\begin{gathered} \left(c\right)70° \\ \begin{array}{l}\text{Here,}\angle \text{ACE}=\angle \text{BAC}={50}^0\left[\text{alternate angles}\right]\\ \text{∠ACB+∠ACE+∠DCE=180° (linear pair)}\\ \angle \text{ACB}={180}^0-(50°+60°)\\ =180°-110°\end{array} \\ =70° \end{gathered}$$