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Question

Marks of high school students are distributed in the table given below.

Marks (Class marks) 2.5 7.5 12.5 17.5 22.5
No. of Students (Frequency) 16 20 12 6 8

Build a histogram and find out the number of students having marks at least 15.

A
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B
8 students have at least 15 marks.
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C
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D
14 students have at least 15 marks.
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Solution

The correct options are
A
D 14 students have at least 15 marks.
We have to first calculate the class interval from the class marks.

Difference between the two successive classes = h = 7.5 - 2.5 =5.

If x is the class marks then, lower and upper boundary of every class is x - h2 and x + h2.
Class marks
(Marks)
Frequency
(No. of students)
Class intervals
2.5 16 0 - 5
7.5 20 5 - 10
12.5 12 10 - 15
17.5 6 15 - 20
22.5 8 20 - 25

Take suitable scale ,
On X-axis 1 cm = 1 class interval
On Y-axis 1 cm = 4 students

Take class intervals on X-axis and frequency on Y-axis.

Now plot the bar in the graph with respect to the class interval.

Students having marks at least 15 is the sum of the frequency of class 15 - 20 and 20 - 25 = 6 + 8 = 14.


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