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Stoichiometry

Mass of calci...

Question

Mass of calcium carbide, ${C a C}_{2}$ , would be needed to produce $150 g$ of acetylene, $C_{2} H_{2}$ by using excess of water?

369.2 g

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184.6 g

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276.9 g

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92.3 g

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Solution

The correct option is B $369.2 g$
$C a C_{2} (s) + 2 H_{2} O (l) ⟶ C a (O H)_{2} (a q) + C_{2} H_{2} (g)$

$1$ mole of $C a C_{2}$ $\equiv 1$ mole of $C_{2} H_{2}$

$∴$ Moles of $C_{2} H_{2} = \frac{150}{26} = 5.769$ moles
$∴$ Moles of $C a C_{2} = 5.769$ moles
$∴$ Moles of $C a C_{2} = 5.769 \times 64$
$= 369.2 g$

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