Question

Match the Column-I with Column-II:

Column-I (Compound)	Column-II (Oxidation state of nitrogen)
(a) $M{g}_3{N}_2$	(P) -1
(b) $NO$	(q) +2
(c) $(N_2{H}_5{)}_{2}S{O}_4$	(r) -2
(d) $N{H}_{2}OH$	(s) -3

• A. a-q, b-s, c-r, d-p
• B. a-s, b-q, c-r, d-p
• C. a-r, b-s, s-q, d-p
• D. a-p, b-s, c-q, d-r

Answer 1

The correct option is B a-s, b-q, c-r, d-p

In $M{g}_3{N}_2$, O.S. of $N=-\frac{6}{2}=-3$
In NO, O.S. of $N=+2$
In $(N_2{H}_5{)}_{2}S{O}_4,$
$4x+10-2-8=0\Rightarrow x=-2$
$\therefore$OS of $N=-2$
In $N{H}_{2}OH,$ OS of $N=-1$