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B
10cm2
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C
24cm2
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Solution
Area=12×base×height ⇒Area=12×2×2=2cm2 Area of quadrilateral PQRT = Area of rectangle PQST + Area of triangle QRS ⇒Area=(4×2)+(12×4×1) Area=8cm2+2cm2=10cm2 Area of hexagon ABCDEF = 6 × Area of triangle AOB Area=6×(12×4×2) ⇒Area=6×4cm2=24cm2