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Question

Match the following expressions and its factors.

Column I Column II
(A) x3+2x2−13x+10 (p) x−2
(B) x2−7x+10 (q) x+5
(C) x2−5x+6 (r) x−3

A
A - q, B - r, C -p
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B
A - r, B - q, C - p
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C
A - r, B - p, C - q
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D
A - q, B - p, C - r
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Solution

The correct option is D A - q, B - p, C - r
Using factor theorem, if xa is factor of p(x), then p(a)=0.

(A)
Substitute 5 for x in x3+2x213x+10, we get:
r=(5)3+2×(5)213×(5)+10
r=125+50+65+10=0
Hence, x+5 is a factor of x3+2x213x+10

B)
Substitute 2 for x in x27x+10, we get:
r=227×2+10
r=414+10=0
Hence, x2 is a factor of x27x+10

C)
Substitute 3 for x in x25x+6, we get:
r=325×3+6
r=915+6=0
Hence, x3 is a factor of x25x+6

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