Metals reacts with hydrogen halides (such as HCl) to give metal halide and hydrogen:
M(s)+nHX(g)→MXn(s)+12nH2(g)
△G=△G(MXn)−n△G(HX(g))
△G(HCl(g))=−95.1kJmol−1
then for the reaction to be product favoured:
A
△G should be negative and △G for MXn should be more negative than (95.1) × n J
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B
△G should be negative and △G for MXn should be more negative than (95.1) × 2n J
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C
△G should be negative and △G for MXn should be more negative than (95100) × n J
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D
△G should be negative and △G for MXn should be more negative than (95100) × 2n kJ
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Solution
The correct option is B△G should be negative and △G for MXn should be more negative than (95100) × n J If a reaction is to be product-favoured, i.e., it is spontaneous in forward side then △G should be negative and △G for MXn should be greater than and more negative than (95.1) × n kJ. So only option C is product favored.