Methyl alcohol is treated with conc HI and red P. The main product obtained is ?

C H_{3} O H

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C H_{4}

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C H_{2} I_{2}

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P H_{3}

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Solution

The correct option is B $C H_{4}$
$H I$ /Red P is one of the strongest reducing agents. So, it reduces all functional groups to yield alkanes. Hence, methanol gives methane.
$C H_{3} O H H I / R e d P \to C H_{4}$

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