You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Factors Affecting Vapour Pressure

Mixture of vo...

Question

Mixture of volatile components of A and B has total vapour presssure (in torr) P=254-119Xa, where Xa is the mole fraction of component A in mixture . hence pure vapour pressure of A and B (in torr)

Open in App

Solution

Suggest Corrections

Similar questions

Q. Mixture of volatile components A and B has total vapour pressure (in torr):
p = 254 – 135

x_{A},

where

x_{A}

is the mole fraction of A in mixture hence

p_{A}^{o}

and

p_{B}^{o}

are (in torr)

Q. A mixture of volatile components A and B has total vapour pressure (in torr) as

P = 254 - 119 χ_{A}

, where

χ_{A}

is the mole fraction of A in the mixture. Hence,

P_{A}^{o}

and

P_{B}^{o}

respectively are (in torr):

Q. Mixture of volatile components A and B has total vapour pressure (in torr):
p = 254 – 135

x_{A},

where

x_{A}

is the mole fraction of A in mixture hence

p_{A}^{o}

and

p_{B}^{o}

are (in torr)

Q. The total vapour pressure,

P_{total}

(in torr) for a mixture of two volatile components,

A

and

B

is given by

P_{total}

= 220 - 110

X_{B}

Where,

X_{B}

is mole fraction of component,

B

in mixture.

Hence, pressure (in torr) of pure components,

A

and

B

are respectively:

At a given temperature, the total vapour pressure (in Torr) of a mixture of volatile components A and B is given by P = 120 - 75 XBhence vapour pressure of pure A and B respectively (in Torr) are -

Join BYJU'S Learning Program