Question

Mohit drops a ball off a 50 m high building. The polynomial $h\left(t\right)=-5t^2+50$ gives the height of the ball, in metres, t seconds after it is dropped. Find the height of the ball from the ground at 𝑡 = 3 seconds.​

• A. 35 m
• B. 45 m
• C. 5 m
• D. 15 m

Answer 1

The correct option is C 5 m

$h\left(t\right)=-5t^2+50$
When $t=3$,
$h\left(3\right)=-5(3{)}^2+50$
$=-45+50$
$=5$
Therefore, the height of the ball is 5 m from the ground.