Question

Mohit makes $8$ full round of a rectangular field with length $=120m$ and breadth $=75m$. John makes $10$ full round of a square field with each side $100$ m.
Find who covers larger distance and by how much?

Answer 1

Given
Length of rectangular field =120 m
Breadth of rectangular field =75 m
Side of square field =100 m
Distance covered by Mohit in one round is equal to the perimeter of the rectangular field
Hence, the perimeter of rectangular field can be calculated as follows :
Perimeter =2 (Length + Breadth)
Perimeter =2×195m
We get,
=390 m
Now, the total distance covered by the Mohit to complete the 8 rounds can be calculated as follows :
Distance =8× perimeter
=8×390
We get,
=3120 m
Distance covered by John in one round is equal to the perimeter of the square field
Hence, the perimeter of square field can be calculated as follows :
Perimitere =4×side
=4×100 m
We get,
=400 m
Therefore the total distance covered by John to complete 10 rounds can be calculated as follows :
Distance=10×Perimeter
=10×400 m
We get,
=4000 m
Difference between the distance covered by Mohit and John is,
4000 m−3120 m
We get,
=880 m
Therefore, John covers larger distance by 880 m than the distance covered by Mohit.