The molar mass of isopentane is 72 g/mol. The expression for the relative lowering of vapor pressure is :
P0−PP0=W2M1W1M2
Substitute values in the above expression.
P0−1445P0=6×72.15114×M2......(1)
P0−1426P0=6×72.1594×M2......(2)
Solving these two equations, we get M2=56.65≈57 g/mol