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Raoult's Law

Mole fraction...

Question

Mole fraction of vapours of A above the solution in a mixture of A and B (X_A=0.4 ) is:

A

0.4

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B

0.8

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C

0.25

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D

None of these

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Solution

The correct option is C
0.25

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Similar questions

Q. Mole fraction of

A

vapours above solution in mixture of

A

B

X_{A} = 0.4

P_{A}^{\circ} = 100 m m, P_{B}^{\circ} = 200 m m

]

Q. Mole fraction of A vapours above the solution in mixture of

A

B

(X_{A} = 0.4)

P_{A}^{\circ} = 100 m m H g

P_{B}^{\circ} = 200 m m H g

]

Mole fraction of vapours of A above the solution in a mixture of A and B (X_A=0.4 ) is:

Q. Mole fraction of A in vapours phase above the ideal liquid solution of A and B

(X_{A} = 0.4)

(P_{A}^{O} = 100 m m P_{B}^{O} = 200 m m)

Q. Mixture of volatile components A and B has total vapour pressure (in torr):
p = 254 – 135

x_{A},

x_{A}

is the mole fraction of A in mixture hence

p_{A}^{o}

p_{B}^{o}

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