Monochromatic light is incident on a metal surface of work function 2.2eV. Photo electrons are emitted from it with a maximum kinetic energy of 0.8eV. Then the wavelength of incident radiation is:
A
6133A0
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B
5133A0
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C
4133A0
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D
7133A0
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Solution
The correct option is B4133A0 KE=hcλ−φ 0.8ev=hcλ−2.2eV hcλ=3×1.6×10−19 20×10−26λ=3×1.6×10−19 λ=4133Ao