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B
12x4y2z−16x3z2
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C
12x4yz−16x3z2
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D
12x4y2z−16x2z2
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Solution
The correct option is B12x4y2z−16x3z2 4x2z(3x2y2−4xz) Multiply each term of the parenthesis by the monomial keeping the addition or subtraction sign same. = 4x2z.3x2y2−4x2z.4xz = 12x4y2z−16x3z2